Momentum of Object in 0.6c Inertia Frame

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SUMMARY

The discussion centers on the calculation of momentum for an object colliding with another object in a rest frame, specifically within an inertial frame moving at 0.6c. The momentum is defined by the equation p=γmv, where γ is the Lorentz factor calculated as γ=1/√(1-β²), with β representing the velocity of the moving frame relative to the speed of light. The conversation highlights the importance of direction in momentum, clarifying that momentum is indeed a vector quantity, contrary to initial misconceptions about its directional properties.

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Outrageous
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The momentum of an object(when it collide with another object in a rest frame) in a inertia frame of 0.6c relative to a rest reference frame.
The momentum is p=γmv.
where γ= 1/√(1-β^2)
m= the mass of an object at the rest frame
v=??
v is the velocity of the moving frame relative to the rest?

But
if the direction of the moving frame is perpendicular to the direction where objects collide.
if the direction of the moving frame is same as the direction where objects collide.
Then both of them have the same momentum? how can?
but the momentum do not have direction?


Thank you.
 
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Momentum does have direction. It's a vector quantity.
 
My mistake:) Thank you
 

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