Monkey Climbing Rope: Solving for the Least Time to Reach a Banana at 6.90m

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A 12.0 kg monkey climbs a rope to reach a banana at 6.90 m, with the rope snapping if tension exceeds 132 N. The calculation begins with using the formula F=ma to determine acceleration, resulting in 11 m/s². Using the kinematic equation, the time to reach the banana is calculated to be approximately 1.12 seconds. The original poster initially doubts their solution but later confirms they resolved the issue. The discussion highlights the importance of correctly applying physics equations to solve motion problems.
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Homework Statement



A 12.0 kg monkey starts to climb a long rope to reach a banana located at a height of 6.90 m. The rope will snap if the tension exceeds 132 N. Calculate the least amount of time the monkey could take to reach the banana without breaking the rope.

Homework Equations



F=ma
x=xo +vot +1/2 at2

The Attempt at a Solution



I know that F=ma, therefore 132=12a
a=11m/s2

Then,
6.90 = 0 + 1/2 (11)t2
t2 = 1.25
t=1.12s

Something must be wrong, please help
 
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nevermind, i solved it!
 
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