More advanced FBD problems-need some tips

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The discussion focuses on advanced Free Body Diagram (FBD) problems requiring calculations and plotting using various computer programs. Participants seek guidance on resolving geometries, determining distances, and expressing angles and tensions as functions of other variables. Key points include the need to simplify equations for distance "a" in terms of known lengths and forces, and the importance of summing forces and moments to achieve equilibrium. Specific examples and equations are provided to illustrate the problem-solving process.

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  • #31
Gokul43201 said:
Some comments :

1. The reaction at B acts normal to the length of the rod.
2. The reaction at A acts vertically downwards.

Calling the angle between the rod and the vertical, X (so that tanX = a/2r) gives :

A + W = BsinX - - - (vertical forces)

P = BcosX - - - (horizontal forces)

Bd = (Wl/2)sinX + (Pl)cosX - - - (moments about A, with d^2 = a^2 + 4r^2)

Okay. So, what do I then use for the X value?

What does the Bd stand for?
 
Last edited:
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  • #32
1. You only need values of sinX and cosX, which are respectively a/\sqrt{a^2 + 4r^2} and 2r/\sqrt{a^2 + 4r^2}.

2. A and B are the normal reaction forces by the pipe on the rod at those corresponding points (sorry about the terrible choice of notation). Perhaps I should have called them N_A, ~N_B.

3. d is the length of the rod inside the pipe. d = \sqrt{a^2 + 4r^2}.
 
  • #33
Gokul43201 said:
1. You only need values of sinX and cosX, which are respectively a/\sqrt{a^2 + 4r^2} and 2r/\sqrt{a^2 + 4r^2}.

2. A and B are the normal reaction forces by the pipe on the rod at those corresponding points (sorry about the terrible choice of notation). Perhaps I should have called them N_A, ~N_B.

3. d is the length of the rod inside the pipe. d = \sqrt{a^2 + 4r^2}.

FINALLY, something that makes sense!:biggrin:

Now, to arrange it all...

Now, I'm completely lost on the second one and a little on the third:
2) http://www.ihostphotos.com/show.php?id=182816"

This was said here:
"at least it's a 90 degree angle! and frictionless ...
try taking Moments around the place where the two F_N intersect
did you sum F_x and F_z first?"

but I just can't, for whatever reason, still figure out what the heck to do. ?

3) http://www.ihostphotos.com/show.php?id=182817"

Again, I was told this:
"this one's pretty easy. Moments around A, gives you T.
back-substitute into Sum F_x and F_z, to get reactions at pin."

and did this so far, until I tried to figure out what the tension TBE was and realized something was wrong:
http://www.ihostphotos.com/show.php?id=192075"

Anything in this one REALLY stick out to you?
 
Last edited by a moderator:
  • #34
Anybody?
 
  • #35
Any help on the second two problems, based on what I said two posts up??
 
  • #36
Anybody?:frown:
 
  • #37
Okay, my last plead...:rolleyes: ...

Can anyone help me figure out #2:
2) http://www.ihostphotos.com/show.php?id=182816

This was said here:
"at least it's a 90 degree angle! and frictionless ...
try taking Moments around the place where the two F_N intersect
did you sum F_x and F_z first?"

but I just can't, for whatever reason, get it going. Where the heck do I take the sum of moments about? And how do I then express the angle (theta) corresponding to equilibrium as a function of M, W, and L?

This is the LAST question for a while, I swear:wink:
 
Last edited by a moderator:

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