More advanced FBD problems-need some tips

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The discussion revolves around tackling advanced Free Body Diagram (FBD) problems that require both calculations and the use of computer programs for plotting. The user seeks guidance on how to approach three specific problems, expressing confusion particularly with geometrical aspects and the relationships between various forces and angles. Key points include the need to express distances and angles as functions of known variables, while also ensuring equilibrium conditions are met through summing forces and moments. The user is encouraged to simplify their equations and clarify the relationships between the forces acting on the system. Overall, the conversation highlights the complexities of applying statics principles in more advanced scenarios.
  • #31
Gokul43201 said:
Some comments :

1. The reaction at B acts normal to the length of the rod.
2. The reaction at A acts vertically downwards.

Calling the angle between the rod and the vertical, X (so that tanX = a/2r) gives :

A + W = BsinX - - - (vertical forces)

P = BcosX - - - (horizontal forces)

Bd = (Wl/2)sinX + (Pl)cosX - - - (moments about A, with d^2 = a^2 + 4r^2)

Okay. So, what do I then use for the X value?

What does the Bd stand for?
 
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  • #32
1. You only need values of sinX and cosX, which are respectively a/\sqrt{a^2 + 4r^2} and 2r/\sqrt{a^2 + 4r^2}.

2. A and B are the normal reaction forces by the pipe on the rod at those corresponding points (sorry about the terrible choice of notation). Perhaps I should have called them N_A, ~N_B.

3. d is the length of the rod inside the pipe. d = \sqrt{a^2 + 4r^2}.
 
  • #33
Gokul43201 said:
1. You only need values of sinX and cosX, which are respectively a/\sqrt{a^2 + 4r^2} and 2r/\sqrt{a^2 + 4r^2}.

2. A and B are the normal reaction forces by the pipe on the rod at those corresponding points (sorry about the terrible choice of notation). Perhaps I should have called them N_A, ~N_B.

3. d is the length of the rod inside the pipe. d = \sqrt{a^2 + 4r^2}.

FINALLY, something that makes sense!:biggrin:

Now, to arrange it all...

Now, I'm completely lost on the second one and a little on the third:
2) http://www.ihostphotos.com/show.php?id=182816"

This was said here:
"at least it's a 90 degree angle! and frictionless ...
try taking Moments around the place where the two F_N intersect
did you sum F_x and F_z first?"

but I just can't, for whatever reason, still figure out what the heck to do. ?

3) http://www.ihostphotos.com/show.php?id=182817"

Again, I was told this:
"this one's pretty easy. Moments around A, gives you T.
back-substitute into Sum F_x and F_z, to get reactions at pin."

and did this so far, until I tried to figure out what the tension TBE was and realized something was wrong:
http://www.ihostphotos.com/show.php?id=192075"

Anything in this one REALLY stick out to you?
 
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  • #34
Anybody?
 
  • #35
Any help on the second two problems, based on what I said two posts up??
 
  • #36
Anybody?:frown:
 
  • #37
Okay, my last plead...:rolleyes: ...

Can anyone help me figure out #2:
2) http://www.ihostphotos.com/show.php?id=182816

This was said here:
"at least it's a 90 degree angle! and frictionless ...
try taking Moments around the place where the two F_N intersect
did you sum F_x and F_z first?"

but I just can't, for whatever reason, get it going. Where the heck do I take the sum of moments about? And how do I then express the angle (theta) corresponding to equilibrium as a function of M, W, and L?

This is the LAST question for a while, I swear:wink:
 
Last edited by a moderator:

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