More advanced FBD problems-need some tips

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Homework Help Overview

The discussion revolves around advanced free body diagram (FBD) problems that require both analytical calculations and the use of computer programs for additional analysis. Participants express that these problems are more complex than previous ones they have encountered, seeking guidance on how to approach them effectively.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need to resolve geometries and express variables such as distance "a" and angles as functions of other parameters. They question how to simplify expressions and the relevance of various forces and moments in their calculations.

Discussion Status

Some participants have offered tips on using moments and forces to approach the problems, while others are still grappling with the complexities of the geometries involved. There is an ongoing exploration of how to express certain variables and the implications of their signs in the context of equilibrium.

Contextual Notes

Participants mention the challenges posed by unknowns in the problems and the requirement to plot relationships between variables as part of their assignment. There is a focus on ensuring that all relevant forces, including the weight of the rod, are accounted for in their calculations.

  • #31
Gokul43201 said:
Some comments :

1. The reaction at B acts normal to the length of the rod.
2. The reaction at A acts vertically downwards.

Calling the angle between the rod and the vertical, X (so that tanX = a/2r) gives :

A + W = BsinX - - - (vertical forces)

P = BcosX - - - (horizontal forces)

Bd = (Wl/2)sinX + (Pl)cosX - - - (moments about A, with d^2 = a^2 + 4r^2)

Okay. So, what do I then use for the X value?

What does the Bd stand for?
 
Last edited:
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  • #32
1. You only need values of sinX and cosX, which are respectively a/\sqrt{a^2 + 4r^2} and 2r/\sqrt{a^2 + 4r^2}.

2. A and B are the normal reaction forces by the pipe on the rod at those corresponding points (sorry about the terrible choice of notation). Perhaps I should have called them N_A, ~N_B.

3. d is the length of the rod inside the pipe. d = \sqrt{a^2 + 4r^2}.
 
  • #33
Gokul43201 said:
1. You only need values of sinX and cosX, which are respectively a/\sqrt{a^2 + 4r^2} and 2r/\sqrt{a^2 + 4r^2}.

2. A and B are the normal reaction forces by the pipe on the rod at those corresponding points (sorry about the terrible choice of notation). Perhaps I should have called them N_A, ~N_B.

3. d is the length of the rod inside the pipe. d = \sqrt{a^2 + 4r^2}.

FINALLY, something that makes sense!:biggrin:

Now, to arrange it all...

Now, I'm completely lost on the second one and a little on the third:
2) http://www.ihostphotos.com/show.php?id=182816"

This was said here:
"at least it's a 90 degree angle! and frictionless ...
try taking Moments around the place where the two F_N intersect
did you sum F_x and F_z first?"

but I just can't, for whatever reason, still figure out what the heck to do. ?

3) http://www.ihostphotos.com/show.php?id=182817"

Again, I was told this:
"this one's pretty easy. Moments around A, gives you T.
back-substitute into Sum F_x and F_z, to get reactions at pin."

and did this so far, until I tried to figure out what the tension TBE was and realized something was wrong:
http://www.ihostphotos.com/show.php?id=192075"

Anything in this one REALLY stick out to you?
 
Last edited by a moderator:
  • #34
Anybody?
 
  • #35
Any help on the second two problems, based on what I said two posts up??
 
  • #36
Anybody?:frown:
 
  • #37
Okay, my last plead...:rolleyes: ...

Can anyone help me figure out #2:
2) http://www.ihostphotos.com/show.php?id=182816

This was said here:
"at least it's a 90 degree angle! and frictionless ...
try taking Moments around the place where the two F_N intersect
did you sum F_x and F_z first?"

but I just can't, for whatever reason, get it going. Where the heck do I take the sum of moments about? And how do I then express the angle (theta) corresponding to equilibrium as a function of M, W, and L?

This is the LAST question for a while, I swear:wink:
 
Last edited by a moderator:

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