Gokul43201 said:
1. You only need values of sinX and cosX, which are respectively a/\sqrt{a^2 + 4r^2} and 2r/\sqrt{a^2 + 4r^2}.
2. A and B are the normal reaction forces by the pipe on the rod at those corresponding points (sorry about the terrible choice of notation). Perhaps I should have called them N_A, ~N_B.
3. d is the length of the rod inside the pipe. d = \sqrt{a^2 + 4r^2}.
FINALLY, something that makes sense!
Now, to arrange it all...
Now, I'm completely lost on the second one and a little on the third:
2) http://www.ihostphotos.com/show.php?id=182816"
This was said here:
"at least it's a 90 degree angle! and frictionless ...
try taking Moments around the place where the two F_N intersect
did you sum F_x and F_z first?"
but I just can't, for whatever reason, still figure out what the heck to do. ?
3) http://www.ihostphotos.com/show.php?id=182817"
Again, I was told this:
"this one's pretty easy. Moments around A, gives you T.
back-substitute into Sum F_x and F_z, to get reactions at pin."
and did this so far, until I tried to figure out what the tension TBE was and realized something was wrong:
http://www.ihostphotos.com/show.php?id=192075"
Anything in this one REALLY stick out to you?