More on linear transformations

johnnyboy2005
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i think I'm just having a hard understanding linear transformations...

i was asked if (5, 0) is a vector in R(T) given by the formula
T(x,y)=(2x-y,-8x + 4y)...i really don't get what I'm supposed to do here.. any hints would be most appreciated.
 
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It asks if the vector (5,0) is in the range of the function T.
So does there exist some vector (x,y), such that T(x,y)=(5,0)?

How would you go about this problem?
 
so much easier now. thank you Galileo
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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