Motion of a jumper - Find the mass

  • Thread starter Jess048
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  • #1
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A high jumper falling at 3.9 m/s, lands on a foam pit and comes to rest, compressing the pit a distance of 0.43 m. If the pit is able to excert an average force of -1100 N on the high jumper in breaking the fall, what is the jumper's mass?

I don't know where to begin so anything can help!!:confused:
 

Answers and Replies

  • #2
Doc Al
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Hint: What was the average acceleration of the jumper during his interaction with the foam?
 
  • #3
HallsofIvy
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Remember that with acceleration -a and initial speed v0, the speed at time t is v(t)= -at+ v0 and the distance moved is x(t)= -(a/2)t2+ v0t. To come to a halt, v(t)= 0= -at+ v0 so requires t= v0/a second. In that time, according to the problem, the jumper moved -(a/2)t2+ v0= 0.43 m. Plug the value of t (as a function of a- you are given v0) into that and solve for a. The solve ma= F(which is given) for m.
 
  • #4
Doc Al
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In applying F = ma, be sure to use the net force on the jumper. (Don't neglect his weight.)
 

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