Motion under a constant force (relativity-related)

AI Thread Summary
The discussion revolves around using the first order Taylor approximation to analyze a particle's speed under a constant force in the non-relativistic limit. Participants clarify that the dimensionless quantity (Ft/m0c) should be treated as small, allowing for simplifications in the equations. The main focus is on deriving the particle's acceleration and confirming its constancy in this limit. There is some confusion regarding the interpretation of epsilon and its relation to the equations provided. Ultimately, the goal is to expand the square root expression to facilitate the calculations.
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Homework Statement



Use the first order Taylor approximation (1 + \epsilon)n \approx 1 + n\epsilon for \epsilon<<1

to see what the particle's speed v(t) is in the non-relativistic limit of small speeds. The specific approximation you'll want to make is that the dimensionless quantity (Ft/m0c) is much less than 1. Show that for very small values of this quantity, the particle's acceleration is constant, and find out what this acceleration is.

Homework Equations



\frac{1}{\sqrt{\frac{1}{Ft/m_{0}}+\frac{1}{c^{2}}}}

The Attempt at a Solution



I'm not sure what the question is asking. Do I use F=ma, and solve for a using the formula? How do I show that it works with Newtonian mechanics? Also, Do I take a limit as \epsilon approaches zero or...what? I don't think I'll have a problem doing the math, I'm just not clear about what is being asked.

Oh, and does epsilon = Ft/mc or just Ft/m? Because Ft/mc isn't in the equation and if I solve for it, the equation may become more complicated to solve for.
 
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You do precisely what the question says; make an expansion of the square root. So first rewrite your expression to something containing
\frac{1}{(1 + \epsilon)^n}
where \epsilon is some quantity which you know is small (one is given in the question, big chance that will be your epsilon).

Don't worry about what epsilon will be, you'll see it roll out of the equation. Just focus on getting a form which you can expand.
 
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