Motion under repulsive electrostatic force

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When two like-charged particles experience a repulsive electrostatic force, they follow a hyperbolic trajectory in the center of mass system, similar to the motion under gravitational attraction but with a different sign in the equations. The force between the particles is described by Coulomb's law, which states that the force is inversely proportional to the square of the distance between them. Each particle's motion can be analyzed using differential equations, although the specific time parameterization remains complex. If one particle is fixed, it occupies one focus of the hyperbola traced by the other particle. For a deeper understanding, advanced mechanics texts like Goldstein's are recommended for derivations related to this motion.
lark
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Is there a simple curve that 2 particles follow when there's a repulsive electrostatic force - like there is for gravitational forces?

I don't know how to solve the differential equation that you get for the
motion.

Laura
 
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When two particles have the same polarity (either both are + charged or - charged), they repel (rather than attract if charges are opposite) each other. The force is proportional to the inverse of the square of the distance (similar to the gravitational force law), and is described by Coulomb's law.

http://hyperphysics.phy-astr.gsu.edu/hbase/electric/elefor.html

Using F = ma = m\ddot{x}, where x is relative to some reference point, e.g. the distance from one charge to the midpoint between the charges, which is then half of the distance between the charges. So there must be an equation of motion for each charge, for which the force is common, and which varies according to the separation of the charges.

If the charges have different masses, then they will have different accelerations, but the force one is the same as the other, even if the charges are of different magnitude.
 
lark said:
Is there a simple curve that 2 particles follow when there's a repulsive electrostatic force - like there is for gravitational forces?

I don't know how to solve the differential equation that you get for the
motion.

Laura
In the cm system, each particle follows a hyperbola.
The DE's are the same as for attractive force (like gravity), but with a different sign for qq'. The full derivation is in advanced mechanics books (like Goldstein), in connection with the classical derivation of the "Rutherford Scattering" cross section.
 
Meir Achuz said:
In the cm system, each particle follows a hyperbola.
The DE's are the same as for attractive force (like gravity), but with a different sign for qq'. The full derivation is in advanced mechanics books (like Goldstein), in connection with the classical derivation of the "Rutherford Scattering" cross section.
Yes, if one particle is fixed in place, it's at a focus of the other
particle's hyperbola! At the other focus than the one it would be at if the force were attractive.

But I don't know what the time parameterization looks like, though I separated the variables to get an integral for time as a function of distance.

Laura
 
lark said:
Yes, if one particle is fixed in place, it's at a focus of the other
particle's hyperbola! At the other focus than the one it would be at if the force were attractive.

But I don't know what the time parameterization looks like, though I separated the variables to get an integral for time as a function of distance.

Laura
If neither particle is fixed, you can use center of mass variables.
I suggest you look into Goldstein for more detail.
 
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