Movement along a straight line w/vector functions

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SUMMARY

The discussion focuses on determining the position vector r(t) of a particle moving along a straight line with a given initial position at (1, -1, 2) and a speed of 2 at time t = 0. The particle accelerates with a constant vector of 2i + j + k towards the point (3, 0, 3). The velocity function is expressed as v(t) = 2ti + tj + tk + c1, where c1 represents the initial velocity vector that must be calculated based on the direction from the initial position to the target point.

PREREQUISITES
  • Vector calculus fundamentals
  • Understanding of vector functions and motion in three dimensions
  • Knowledge of initial conditions in kinematics
  • Familiarity with acceleration and velocity concepts
NEXT STEPS
  • Calculate the initial velocity vector c1 using the direction from (1, -1, 2) to (3, 0, 3)
  • Explore the integration of acceleration vectors to derive velocity functions
  • Learn how to derive position vectors from velocity functions in vector calculus
  • Study the application of kinematic equations in three-dimensional motion
USEFUL FOR

Students studying physics or mathematics, particularly those focusing on kinematics and vector functions, as well as educators looking for examples of motion in three dimensions.

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Homework Statement


A particle traveling in a straight line is located at the point (1, -1, 2) and has speed 2 at time t = 0. The particle moves toward the point (3, 0, 3) with constant acceleration 2i + j + k. Find its position vector r(t) at time t.

Homework Equations


Speed = |v|

The Attempt at a Solution


v(t) = 2ti + tj + tk + c1
I don't know how to find c1 from here.

Thanks in advance!
 
Last edited:
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c1 is v(0). c1 should be vector pointing along the direction from (1,-1,2) to (3,0,3) with length 2, right? Sure you can't find that?
 

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