Multiple eigenvalues - any hints would be appreciated

WantToBeSmart
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Homework Statement



I need to prove that a 4x4 matrix has 2 zero eignenvalues.

2. The attempt at a solution

I have tried to obtain the characteristic equation but calculating the determinant of a relevant 4x4 is rather daunting as there aren't many zeros.

I was wondering if there is any other way to prove the statement without resorting to this brute force approach.

Thank you in advance!
 
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I assume you mean that you have a specific 4 by 4 matrix that you have not shown us. No, there is no 'simple' way to calculate eigenvalues except for special matrices. Whether or not there exist a special trick for your matrix, we cannot say because you do not show us the matrix. Just calculate the determinant of A- \lambda I and set it equal to 0. With a f4 by 4 matrix that will give you a fourth degree polynomial equation.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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