Use the given transformation to evaluate the given integral, where R is the parallelogram with vertices (-2, 2), (2, -2), (4, 0), and (0, 4).(adsbygoogle = window.adsbygoogle || []).push({});

∫∫(2x+8y)dA; x=1/2(u+v) y=1/2(v-u)

I found the bounds of the parallelogram of -4≤u≤4 and 4≤v≤0

so i set the equation to be

∫∫(2(1/2(u+v))+8(1/2(v-u))dudv with the bounds been written in there

am i on the right track

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# Homework Help: Multiple Integrals with parallelogram

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