Mutual Inductance: Understanding J2X2

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Discussion Overview

The discussion revolves around the concept of mutual inductance, specifically focusing on the term J2X2 within the context of mesh analysis for calculating mesh currents in a circuit diagram. Participants are exploring the derivation and implications of this term in relation to coupled inductors.

Discussion Character

  • Exploratory, Technical explanation, Conceptual clarification

Main Points Raised

  • One participant expresses confusion about the origin of the term J2X2 in the second mesh equation, despite understanding other terms in the first mesh equation.
  • Another participant suggests that the first occurrence of J2 is due to the current I2 in inductor j6, which induces a voltage of I2*j2 in inductor j8.
  • It is noted that the current I2 in inductor j8 also induces a voltage of I2*j2 in inductor j6, highlighting the interdependence of the two inductors in the mesh analysis.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the origin of J2X2, as the initial confusion remains, but there is an acknowledgment of the explanation provided regarding the mutual inductance effects.

Contextual Notes

The discussion does not clarify the specific definitions or assumptions related to the inductors or the circuit configuration, which may affect the understanding of the term J2X2.

salman213
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1.I don't understand where the J2X2 comes from. Everything else seems fine but why is there a J2x2 CHECK ATTACHED PICTURE



THANK YOU
 

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Maybe post the picture somewhere else or explain.
 
well basically I am trying to do mesh analysis to calculate the mesh currents in that picture...

umm...those are the two equations that the book shows. I understand where all the terms in the first mesh equation come from, but I am confused about where j2x2 comes from in the 2nd mesh equationAnyone
know?
 
What you have is j2 occurring twice.

The first one is caused by current I2 in inductor j6; that causes a voltage of I2*j2 to be induced in the j8 inductor.

Then, the I2 current in inductor j8 also causes a voltage of I2*j2 to be induced in inductor j6.

When you have two coupled inductors in series in a loop, such as the I2 loop, the current in each inductor causes a voltage drop in that same inductor, but it also causes a voltage drop in the other inductor.
 
Thanks makes sense :)
 

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