Solving Limit of $\log {(n+1)}/\log {n}$

  • Thread starter steven187
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It should be \log{n}+\log{(n(1+1/n))} instead of \log{n}+\log{n(1+1/n)}.In summary, a user was asking for help with a limit problem they encountered while working on a proof. Another user provided a solution, which involved simplifying the limit to 1+log(1+1/n)/log(n). The original poster then confirmed that the solution looked correct, with a small typo correction.
  • #1
steven187
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hello all

I was workin on a problem and during my proof I came to this problem does anybody know what happens with this limit

[tex]\lim_{n\rightarrow\infty} \frac{\log {(n+1)}}{\log {n}}[/tex]

thanxs
 
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  • #2
HINT: n+1 = n(1+1/n)
 
  • #3
hello all

would this be correct?

[tex]\lim_{n\rightarrow\infty} \frac{\log {(n+1)}}{\log {n}}[/tex]
[tex]=\lim_{n\rightarrow\infty} \frac{\log {n(1+\frac{1}{n})}}{\log {n}}[/tex]
[tex]=\lim_{n\rightarrow\infty} \frac{\log{n}+\log {n(1+\frac{1}{n})}}{\log {n}}[/tex]
[tex]=1+\lim_{n\rightarrow\infty} \frac{\log {(1+\frac{1}{n})}}{\log {n}}=1[/tex]
 
  • #4
yes that looks right except that you have a typo in the 3rd equation.
 

What is the limit of $\log {(n+1)}/\log {n}$ as n approaches infinity?

The limit of $\log {(n+1)}/\log {n}$ as n approaches infinity is equal to 1. This can be proven using the properties of logarithms and the limit definition.

Why is the limit of $\log {(n+1)}/\log {n}$ important in mathematics and science?

The limit of $\log {(n+1)}/\log {n}$ is important because it helps us understand the growth rate of functions. It can also be used to analyze the complexity of algorithms and the rate of convergence of sequences.

How do you solve the limit of $\log {(n+1)}/\log {n}$?

The limit of $\log {(n+1)}/\log {n}$ can be solved using L'Hopital's rule or by using the definition of a limit. It involves simplifying the expression and then evaluating the limit as n approaches infinity.

Can the limit of $\log {(n+1)}/\log {n}$ be extended to other logarithmic functions?

Yes, the limit of $\log {(n+a)}/\log {n}$ can be extended to other logarithmic functions, where a is any constant. The result will still be equal to 1 as n approaches infinity.

How does the limit of $\log {(n+1)}/\log {n}$ relate to the concept of asymptotes?

The limit of $\log {(n+1)}/\log {n}$ is equal to 1, which means that the function has a horizontal asymptote at y=1. This means that the function approaches 1 as n approaches infinity, but will never actually reach it.

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