Need a little help starting this integral

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silverdiesel
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[tex]\int\frac{1}{e^x+1}dx[/tex]

I have tried substitution, partial fraction decomposition, and integration by parts but I can't seem to figure it out. Any help is much appriciated. o:)
 
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okay, then I can use u sub, which nets...

[tex]-ln (1+e^{-x})[/tex]

is that right?
 
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That does not seem right. What I have I done wrong?

[tex]\int\frac{e^{-x}}{1+e^{-x}}dx[/tex]

[tex]u = 1+e^{-x}\\-du = e^{-x}[/tex]

[tex]-\int\frac{1}{u}du[/tex]
 
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silverdiesel said:
That does not seem right. What I have I done wrong?

[tex]\int\frac{e^{-x}}{1+e^{-x}}dx[/tex]

[tex]u = 1+e^{-x}\\-du = e^{-x}[/tex]

[tex]-\int\frac{1}{u}du[/tex]

It looks right to me, why do you think it's wrong?
 
After further review, I don't think its wrong. I guess I am just working on building confidence in the integration process and I was hoping for some confirmation that is was done right. Thank you. These forums have been extremely helpful and I really appreciate all the quick and intelligent responces.