Need explanation of this differential equation

aruwin
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I need explanations at the last part of this math solution.

Question:
Solve the differential equation:
y' = (1 + 2/x)y

Answer:
ln|y| = x+ln(x^2)+c

|y| = e^c.x^2.e^x

y = Cx^2.e^x (C = +/-e^c is any constant that is not equals to 0)

What I don't understand is this part where : |y| = e^c.x^2.e^x
Why do we have to multiply all the terms when we take the "In" out?
 
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Because what you do to one side has to be done to the other and ##a^{(b+c)}=a^ba^c## ... step by step:

starting from:
##\ln|y|=x+\ln(x^2)+c## ... take the exponential of both sides:

##y=e^{x+\ln(x^2)+c}=e^x e^{\ln(x^2)}e^c##
 
The symbol is not "In" it is "ln" for logarithm.
 
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