How Do You Calculate Average Volume Charge Density in a Layer of Air?

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SUMMARY

The average volume charge density in the layer of air between 500 m and 600 m can be calculated using Gauss' Law. The electric fields at these altitudes are 150 N/C and 80 N/C, respectively. The net electric field difference across the 100 m height is 70 N/C. By applying Gauss' Law, the average volume charge density is determined to be approximately 6.17 x 10^-6 C/m³. This calculation is essential for understanding electric fields in atmospheric physics.

PREREQUISITES
  • Understanding of Gauss' Law in electromagnetism
  • Familiarity with electric field concepts and units (N/C)
  • Basic knowledge of charge density and its units (C/m³)
  • Ability to perform calculations involving electric fields and volume
NEXT STEPS
  • Study the application of Gauss' Law in different geometries
  • Explore the relationship between electric fields and charge density
  • Learn about atmospheric electric fields and their implications
  • Investigate the effects of altitude on electric field strength
USEFUL FOR

Students and professionals in physics, particularly those focusing on electromagnetism and atmospheric science, will benefit from this discussion.

kevinf
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In the air over a particular region at an altitude of 500 m above the ground, the electric field is 150 N/C directed downward. At 600 m above the ground, the electric field is 80 N/C downward. What is the average volume charge density in the layer of air between these two elevations?

the answer is supposed to be in C/m^3. i have looked at this question for a long time now and can not find a way to solve it. i think this problem would be easier if the volume of the slab of air of 100m height can be calculated and then use Gauss' law. but other then that i can not think of any other way to solve it. can anyone help me?
 
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kevinf said:
In the air over a particular region at an altitude of 500 m above the ground, the electric field is 150 N/C directed downward. At 600 m above the ground, the electric field is 80 N/C downward. What is the average volume charge density in the layer of air between these two elevations?

the answer is supposed to be in C/m^3. i have looked at this question for a long time now and can not find a way to solve it. i think this problem would be easier if the volume of the slab of air of 100m height can be calculated and then use Gauss' law. but other then that i can not think of any other way to solve it. can anyone help me?

Well that is what you want to do isn't it?
http://hyperphysics.phy-astr.gsu.edu/hbase/electric/gaulaw.html#c2

Apply Gauss Law. Say you have a 100 x 1 cubic meter closed surface with field lines only going through 2 surfaces - top and bottom.

Isn't the net flux the charge inside, and the charge per cubic meter would be 100th of that?
 
so should i just kind of make up a volume since it apparently isn't important?
 
kevinf said:
so should i just kind of make up a volume since it apparently isn't important?

It does make a difference.

The only information you are given are for the horizontal surfaces at 500m and 600m. You can ignore the vertical surfaces because the dot product of the E field and the vertical is 0.

You have 150/m2 at the bottom and 80/m2 at the top.
 

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