- #1
Sneakatone
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An automobile of mass 1500 kg traveling at 24 m/s crashes into a similar parked automobile. The two automobiles remain joined together after the collision. Suppose that the collision last for 0.020s, and pavement with a coefficient of friction uk=0.63. What change of momentum and what change of speed does the friction force produce in the joined automobiles in the interval of 0.020 s ?
Delta p=?
Delta v=?
for p I did 24m/s *1500kg=36000
3600/12m/s=3000
The Friction force = µ . m . g =0.63*9.81*3000=18541 N
The change in momentum produced by this force = F . t =18541*0.02=371 kg*m/s
delta p=36000-371=35629 kg*m/s
to get v
35629/3000=11.87m/s
12m/s-11.87m/s=0.15 m/s
Delta p=?
Delta v=?
for p I did 24m/s *1500kg=36000
3600/12m/s=3000
The Friction force = µ . m . g =0.63*9.81*3000=18541 N
The change in momentum produced by this force = F . t =18541*0.02=371 kg*m/s
delta p=36000-371=35629 kg*m/s
to get v
35629/3000=11.87m/s
12m/s-11.87m/s=0.15 m/s