Need help in deriving this reduction formula

hms.tech
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It might be difficult for you to read this integral in non latex form, but i'll try my best.
As i don't know how to write this in latex form, assume "for this problem" that I(n) is pronounced as "I subscript n" or nth term of I.


Homework Statement



I(n)=∫ (sinx)^n dx [with limits of the integral as : from zero (0) to ∏/2 (pi/2)

Using the above equation, it is required to prove that :

I(n+2)= I(n) * (n+1)/(n+2) [again , I(n) means I subscript n ie nth term of a sequence]

Homework Equations


the formula for integration by parts


The Attempt at a Solution



I have tried to integrate it by parts using various ways but all of them failed to prove the required result.
One of them was :
∫ [sin^-2(x)*(sin(x))^(n+2)] dx [with the same limits ofcourse]

even after subsituting 1-cos^2(x) for sin^2(x) the problem could not be solved,
please help me solve it.
 
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hms.tech said:
It might be difficult for you to read this integral in non latex form, but I'll try my best.
As i don't know how to write this in latex form, assume "for this problem" that I(n) is pronounced as "I subscript n" or nth term of I.


Homework Statement



I(n)=∫ (sinx)^n dx [with limits of the integral as : from zero (0) to ∏/2 (pi/2)

Using the above equation, it is required to prove that :

I(n+2)= I(n) * (n+1)/(n+2) [again , I(n) means I subscript n ie nth term of a sequence]

Homework Equations


the formula for integration by parts


The Attempt at a Solution



I have tried to integrate it by parts using various ways but all of them failed to prove the required result.
One of them was :
∫ [sin^-2(x)*(sin(x))^(n+2)] dx [with the same limits of course]

even after substituting 1-cos^2(x) for sin^2(x) the problem could not be solved,
please help me solve it.
Start with In+2.
Even without LaTeX, you can do SUBSCRIPTS and SUPERSCRIPTS by using the X2 and X2 buttons in the 'Go Advanced' message window.

\displaystyle I_{n+2}=\int\sin^{n+2}(x)\,dx=\int(1-\cos^2(x))\sin^{n}(x)\,dx=I_n-\int\cos^2(x)\sin^{n}(x)\,dx

Evaluate that last integral using integration by parts.
u=cos(x), dv=cos(x)sinn(x) dx​
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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