- #1

Hertz

- 180

- 8

I think it's something like: E = hf, but I'm not sure.

Any help is appreciated :)

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- Thread starter Hertz
- Start date

- #1

Hertz

- 180

- 8

I think it's something like: E = hf, but I'm not sure.

Any help is appreciated :)

- #2

whybother

- 166

- 0

E = hf

Yup. I assume you mean for EM waves?

- #3

Hertz

- 180

- 8

Yup, is that the right equation?

- #4

whybother

- 166

- 0

Yes.

- #5

Hertz

- 180

- 8

So does this mean that everything with mass is actually an EM wave? Sorry I don't know a whole lot, I'm still in 11th grade :\

- #6

whybother

- 166

- 0

No, that's not what it means, that's why I asked if you meant for EM waves.

While yes, all matter does have an associated wavelength, but no, you can't compare the rest mass energy to the energy for an EM wave.

You should read about http://en.wikipedia.org/wiki/Wave-particle_duality" [Broken] if you are curious.

For photons, [tex]E=h f[/tex] where the momentum of a photon is given by,

[tex]p = {E \over c}[/tex]

Generalized to massive particles, we get

[tex]\lambda = {h \over p} [/tex]

Where [tex]\lambda[/tex] is the associated wavelength.

In general, energy is not just the rest mass energy and also includes a momentum term, so for our massive particles we have: [tex]E^2 = m^2 c^4 + p^2 c^2[/tex]

While yes, all matter does have an associated wavelength, but no, you can't compare the rest mass energy to the energy for an EM wave.

You should read about http://en.wikipedia.org/wiki/Wave-particle_duality" [Broken] if you are curious.

For photons, [tex]E=h f[/tex] where the momentum of a photon is given by,

[tex]p = {E \over c}[/tex]

Generalized to massive particles, we get

[tex]\lambda = {h \over p} [/tex]

Where [tex]\lambda[/tex] is the associated wavelength.

In general, energy is not just the rest mass energy and also includes a momentum term, so for our massive particles we have: [tex]E^2 = m^2 c^4 + p^2 c^2[/tex]

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