Need help understanding time dilation

annms
Messages
15
Reaction score
3
I keep reading that an observer will find the clock moving relative to him to be slower than his own local clock. But isn't his own local clock measuring proper time, which should be a shorter time period than the moving clock? How can the slower (moving) clock measure a longer time period? Isn't that a contradiction? I'm so confused please help.
 
Physics news on Phys.org
annms said:
I keep reading that an observer will find the clock moving relative to him to be slower than his own local clock.
Right.
But isn't his own local clock measuring proper time, which should be a shorter time period than the moving clock?
Proper time between what events?
How can the slower (moving) clock measure a longer time period?
A slower clock measures less time between events, of course.

If the 'events' are the ticks of the moving clock, then it is the moving clock that measures the proper time between them. Not you! (Your clocks measure proper time between events that occur at your location.)

Say you are observing a rocket speeding by. The rocket has a clock that is set to flash a burst of light every time a minute passes. You, using your own Earth clocks, would say that the time between flashes was greater than one minute and thus you would describe the moving clock on the rocket as running slow. Since the flashes take place at the location of the moving clock, that clock measures the proper time between them.
 
Last edited:
Thanks. I think I'm getting it a little better.

This was what really confused me: Let's say a spaceship is traveling at a speed near c relative to earth. If one hour has elapsed according to an Earth observer's clock, how much will have elapsed in the spaceship's clock according to the Earth observer? (ie. greater than one hour or less than one hour?) And why?
 
annms said:
If one hour has elapsed according to an Earth observer's clock, how much will have elapsed in the spaceship's clock according to the Earth observer? (ie. greater than one hour or less than one hour?)
The Earth observer would say that during the one hour on earth, less than an hour would have elapsed on the spaceship clock.
And why?
Moving clocks run slowly.
 
Annms:

What do you think the rapidly moving spaceship observer will say about the elapsed time he observes on earth??

Hint: who is moving rapidly now??
 
Thread 'Can this experiment break Lorentz symmetry?'
1. The Big Idea: According to Einstein’s relativity, all motion is relative. You can’t tell if you’re moving at a constant velocity without looking outside. But what if there is a universal “rest frame” (like the old idea of the “ether”)? This experiment tries to find out by looking for tiny, directional differences in how objects move inside a sealed box. 2. How It Works: The Two-Stage Process Imagine a perfectly isolated spacecraft (our lab) moving through space at some unknown speed V...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. The Relativator was sold by (as printed) Atomic Laboratories, Inc. 3086 Claremont Ave, Berkeley 5, California , which seems to be a division of Cenco Instruments (Central Scientific Company)... Source: https://www.physicsforums.com/insights/relativator-circular-slide-rule-simulated-with-desmos/ by @robphy
In Philippe G. Ciarlet's book 'An introduction to differential geometry', He gives the integrability conditions of the differential equations like this: $$ \partial_{i} F_{lj}=L^p_{ij} F_{lp},\,\,\,F_{ij}(x_0)=F^0_{ij}. $$ The integrability conditions for the existence of a global solution ##F_{lj}## is: $$ R^i_{jkl}\equiv\partial_k L^i_{jl}-\partial_l L^i_{jk}+L^h_{jl} L^i_{hk}-L^h_{jk} L^i_{hl}=0 $$ Then from the equation: $$\nabla_b e_a= \Gamma^c_{ab} e_c$$ Using cartesian basis ## e_I...

Similar threads

Back
Top