Need help with an inelastic collision problem

AI Thread Summary
To find the speed of the car before the inelastic collision, use the conservation of momentum and energy principles. The final momentum after the collision can be calculated as the combined mass of both cars multiplied by their final velocity, which is affected by friction. The force of friction can be determined using the coefficient of friction and the weight of the cars, allowing for the calculation of work done by friction over the distance they slid. By equating the initial kinetic energy to the final kinetic energy minus the work done by friction, the initial velocity of the second car can be determined. This approach effectively combines momentum conservation with energy principles to solve the problem.
formulajoe
Messages
177
Reaction score
0
A car weighing 900 kg is waiting at a stop sign. A car weighing 1200 kg hits the oter car. The cars move .76 m after the collision. The coefficient of friction between the sliding tires and the pavement is .92. I need to find the speed of the car right before the collision.
I don't know what to use. Conservation of momentum doesn't work because I need at least one of the velocities.
 
Physics news on Phys.org
formulajoe,
I think conservation of momentum is the right idea. I think you got to use it.
You got to find the final momentum. The idea is that the cars stick together after collision. So the final momentum is (m_1 + m_2)v_{final}. You got to find v_{final}.
You can do that. The cars are decelerated by a constant force of friction. This force is F = .92(m_1 + m_2)g. From F and d = .76m you can calculate v_{final}.
 


To solve this problem, you can use the conservation of energy principle. First, calculate the total kinetic energy of the cars before the collision using the formula KE = 1/2 * m * v^2, where m is the mass of the car and v is the velocity. Since the car at the stop sign is not moving, its initial kinetic energy will be zero.

Next, use the coefficient of friction and the distance the cars moved after the collision to calculate the work done by friction on the cars. This can be done using the formula W = F * d, where F is the force of friction and d is the distance. The force of friction can be calculated using the coefficient of friction and the weight of the cars (F = u * m * g).

Now, we can equate the initial kinetic energy to the final kinetic energy (after the collision) minus the work done by friction. This will give us an equation to solve for the initial velocity of the second car (since the first car is at rest). Once we have the initial velocity of the second car, we can use the conservation of momentum principle (m1v1 + m2v2 = m1v1' + m2v2') to find the initial velocity of the first car.

I hope this helps you solve the problem. Remember to always double check your units and make sure they are consistent throughout the calculations. Good luck!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top