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Need help solving this problem
http://img409.imageshack.us/img409/5854/chp851yx1.jpg [Broken]
Thank you
http://img409.imageshack.us/img409/5854/chp851yx1.jpg [Broken]
Thank you
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Conservation of mmtm states that mmtm before=mmtm after. Think of the total system. Before the block starts moving, like you said, p_{i}=0. When the block hits the horizontal surface, the total momentum p_{f}= 0.5*4-v_{2}*m_{2}. (The negative sign appears, since the block moves to the left.) From this you can find the velocity of the wedge.the momentum before the release is 0, and after is 2. I understand that i need to apply conservation of momentum in this problem somehow, but I dont see a way so far.
v2 = 2/3 m/s ( to the left) ?
and for part b, should I use convservation of energy (potential and kinetic) in order to find the height?
You're very welcome!thank you very much for your help