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## Homework Statement

Take the derivative of:

[tex] f(x) = \frac{sin(x^2)}{ln sinx}[/tex]

## Homework Equations

Here's the formula I used (and always do) for the chain rule:

[tex] \frac{d}{dx}[f(g(x))] = f'(g(x))*g'(x) [/tex]

## The Attempt at a Solution

[tex] f'(x) = \frac{ln sinx(cos(x^2)2x) - sin(x^2)\frac{1}{sinx}sinx cosx}{[ln sinx]^2}[/tex]

So, I've done this simple derivative problem 3 times and for some reason I keep getting this answer. E-Mailed my Prof and he said that the sinx right after the 1/sinx is not suposed to be there, but I cannot see why...Can anyone verify the correct answer for me just to see what I'm not grasping here. I'm very frustrated.