Need some series/ summation help

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\sum_{n=1}^{\infty}(-1)^{n}\frac{e^{-\frac{1}{nx}}}{n}

Where 0<x<oo.

I'm looking for a closed form/ closed representation for this series [I was thinking something like a polylogarithm or dirichlet eta function combination might work].

Any ideas or suggestions would be much appreciated.
 
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it does not converge...
 
soandos said:
it does not converge...

Sure it does, it differs from \sum_{n=1}^\infty \frac{(-1)^n}{n} by an absolutely convergent series.
 
If (-1)^n is being raised to \frac{e^{-\frac{1}{nx}}}{n}, i do not believe it converges. (it can also be simplified, the n's go away). please clarify what you mean.
 
I understand the confulsion. If you read the TeX code included, you can see what was actually written. The term to be summed is (-1)^n times a fraction:
\sum_{n=1}^{\infty}\;(-1)^{n}\left(\frac{e^{-\frac{1}{nx}}}{n}\right)
 
g_edgar said:
I understand the confulsion. If you read the TeX code included, you can see what was actually written. The term to be summed is (-1)^n times a fraction:
\sum_{n=1}^{\infty}\;(-1)^{n}\left(\frac{e^{-\frac{1}{nx}}}{n}\right)

Sorry about the confusion. I should have included the brackets as you demonstrated.
 
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