Need to know how to solve for test

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To solve the problem of a 2.0kg box on an inclined plank, first resolve the gravitational force into components along and perpendicular to the plank. The force of gravity acting on the box is 19.6 N, which can be split into a component parallel to the incline and one perpendicular to it. The maximum static friction force can be calculated using the coefficient of static friction (0.19) multiplied by the normal force. By setting the sum of forces equal to zero at the point of impending motion, the spring force can be determined, allowing for the calculation of the maximum stretch of the spring. The final result shows that the spring can be stretched a maximum of 6.6 cm while keeping the box at rest.
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A 2.0kg box rests on a plank that is inclined at a angle of 65 degrees above the horizontal. The upper end of the box is attached to a spring with a force constant of 295 N/m. If the coefficient of the static friction between the box and the plank is 0.19, what is the maximum amount the spring can be stretched and the box remain at rest?

Can someone show me how to complete this problem. The answer is 6.6cm however I don't know to get there. thanks

I also know that I have to find force and divide that by 295N/M to get answer can someone help me find force please! What numbers do I use
 
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Get expressions for the forces on the box in the direction of the plank. You'll need to resolve the mg force into a component along the plank and another perpendicular to the plank that you can use to find the friction forces. Set the sum of the forces equal to zero - the point where it will just begin to move. That should allow you to solve for the stretch.
 
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