1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Negation statement

  1. Mar 1, 2009 #1
    Statement:

    ([tex]\exists_{x} \in [/tex] R) ([tex]\forall_{y} \in [/tex] R) (3x + 2y = 7)

    Trying to find negation statement. This is what I think it is:

    ([tex]\forall_{x} \in [/tex] R)([tex]\exists_{y} \in [/tex] R) (3x + 2y ≠ 7)


    Is this close?
     
  2. jcsd
  3. Mar 1, 2009 #2
    I'm having trouble reading this notation, but I'm assuming the first statement says "There exists an x in R such that for all y in R, 3x + 2y = 7."

    To make this backwards, we would need to say, "For each x in R, there exists a y in R such that 3x + 2y does not equal 7," so if I have interpreted your notation correctly, I think your answer is correct.
     
  4. Mar 1, 2009 #3
    Thanks, phreak. Yes, that is how it should read.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Negation statement
  1. Negating a Statement (Replies: 2)

Loading...