Net Electric field and electric net force

  • Thread starter lonlyway
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  • #1
lonlyway
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Homework Statement


well, I'm solving one question from 12U physics, and my answer don't match with others.

the question is at attached file. I do not know how to put it in here


Fex = 1.35, Fey = 1.35, and Fnet = 1.91 (45°)
this one make sense, however on next one, which is

"What is the net electric field acting on charge 1"

I think using equation, Fe = qε, and q is 3 x 10-5,
both εx and εy should be 1.35/(3 x 10-5)

however the answer that I've match with this says

Fex = εx and the marker says it is correct.

how does people think I should solve this?

Homework Equations


Fe = kq1q2/r2 = qε

ε=kq/r2
 

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Answers and Replies

  • #2
Simon Bridge
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think using equation, Fe = qε, and q is 3 x 10-5,
both εx and εy should be 1.35/(3 x 10-5)
Charge 1, on your attachment, is 20μC .
Thus the net electric field should be the net force (1.91N) divided by 2x10-5.
Since the charge is positive, the field vector points the same way as the force.

Fex = εx and the marker says it is correct.
Doesn't make sense to me either.
 
  • #3
lonlyway
5
0
Charge 1, on your attachment, is 20μC .
Thus the net electric field should be the net force (1.91N) divided by 2x10-5.
Since the charge is positive, the field vector points the same way as the force.

Doesn't make sense to me either.

Thanks for the conformation
 

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