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thua
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1. A 1.2 x 10^4 kg truck is traveling south at 22 m/s.
a) What net force is required to bring the truck to a stop in 330 m?
b) What is the cause of this net force?
Answer: a) 8.0 x 10^3 N [N]
2. Each of the four wheels of a car pushes on the road with a force of 4.0 x 10^3 N [down]. The driving force on the car is 8.0 x 10^3 N [W]. The frictional resistance on the car is 6.0 x 10^3 N [E]. Calculate the following:
a) the mass of the car
b) the car's acceleration
Answer: a) 1.6 x 10^3 kg b) 1.2 m/s^2 [W]
I have the answers to these two questions, but I really need help on how to understand and do it.
So far...
1. a) v = d/t
t = d/v
t = (0.33 km)/(22 m/s)
t = 0.015 s
a = v/t
a = (22 m/s)/(0.015 s)
a = 1466.7 m/s^2 ?? <====== stopped here because this makes no sense..
a) What net force is required to bring the truck to a stop in 330 m?
b) What is the cause of this net force?
Answer: a) 8.0 x 10^3 N [N]
2. Each of the four wheels of a car pushes on the road with a force of 4.0 x 10^3 N [down]. The driving force on the car is 8.0 x 10^3 N [W]. The frictional resistance on the car is 6.0 x 10^3 N [E]. Calculate the following:
a) the mass of the car
b) the car's acceleration
Answer: a) 1.6 x 10^3 kg b) 1.2 m/s^2 [W]
I have the answers to these two questions, but I really need help on how to understand and do it.
So far...
1. a) v = d/t
t = d/v
t = (0.33 km)/(22 m/s
t = 0.015 s
a = v/t
a = (22 m/s
a = 1466.7 m/s^2
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