- #61
shaltera
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Zth=(330.3+j219)
Zl=(330.3-j219)
Zl=(330.3-j219)
Network Maximum Power Transfer Calculation
- Thread starter shaltera
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- Maximum Maximum power Power
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SUMMARY
The discussion focuses on calculating the load impedance that maximizes power transfer in an AC circuit using the Maximum Power Transfer Theorem (MPTT) and Thevenin's theorem. The participants clarify that the load impedance should equal the complex conjugate of the Thevenin impedance for maximum power transfer. Key calculations include determining Thevenin impedance (ZTH = 330.3 + j219.8 Ω) and deriving the load impedance (ZL = 330.3 - j219.8 Ω). The conversation emphasizes the importance of frequency in determining impedance and the need to express power in terms of real values.
PREREQUISITES- Thevenin's Theorem
- Maximum Power Transfer Theorem (MPTT)
- Complex Impedance Analysis
- AC Circuit Analysis
- Study the derivation of the Maximum Power Transfer Theorem for complex impedances.
- Learn how to calculate Thevenin voltage in AC circuits.
- Explore the relationship between frequency and impedance in AC circuits.
- Review examples of AC circuits with reactive components and their power calculations.
Electrical engineering students, circuit designers, and anyone involved in AC circuit analysis and optimization will benefit from this discussion.
- #62
gneill
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shaltera said:
Okay, and how are they connected in the circuit?
- #63
shaltera
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In series
- #64
shaltera
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Znet=Zth+Zl=660.6?
- #65
gneill
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shaltera said:
Yes!
Note that the reactive components have completely disappeared. The choice for ZL as the complex conjugate of Zth has ensured that the reactive components cancel each other.
So for purposes of analysis at this point, the source impedance is just a real resistance of 330Ω, and the load impedance is just a real resistance 0f 330Ω. Two resistors! Easy to analyze!
Can you find the power in that load resistor? Remember that the source voltage is Vth.
- #66
shaltera
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P=i2Rl
- #67
gneill
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That'll work; So how will you calculate the current? Remember, the load circuit now comprises the Thevenin voltage (1000/1220)E and two resistors of the same size (330 Ω).
(Actually, the notion that the two resistors form a voltage divider might give you another path to finding the power, particularly since it's a very simple voltage divider with equal value resistors...)
(Actually, the notion that the two resistors form a voltage divider might give you another path to finding the power, particularly since it's a very simple voltage divider with equal value resistors...)
- #68
shaltera
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I=Vth/(Zth+Rl)
- #69
gneill
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shaltera said:
Remember: The voltage source Vth sees ONLY the resistances. The reactive (imaginary) part of Zth has "disappeared", cancelling with the reactive part of the load impedance.
- #70
shaltera
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Zth=(330.3+j219)
Zl=(330.3-j219)
I=E(1000/1220)(330.3)
Zl=(330.3-j219)
I=E(1000/1220)(330.3)
- #71
gneill
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