Neutral conductor has a hollow cavity within it

AI Thread Summary
A neutral conductor with a hollow cavity will have a charge of -6.3 nC on its inner surface when a +6.3 nC point charge is placed inside, due to the attraction of negative charges toward the positive point charge. The outer surface will then have a charge of +6.3 nC as positive charges are repelled to the outer surface. If the conductor is grounded, the inner surface remains at -6.3 nC, but the outer surface becomes 0 nC since excess positive charge can flow to the ground. If the conductor initially has a net charge of +4·q, the inner and outer surface charges need to be recalculated based on this initial charge. Understanding these concepts can be aided by applying Gauss's theorem, which states that there is no electric field inside a conductor.
TwinCamGTS
Messages
18
Reaction score
0

Homework Statement



a neutral conductor has a hollow cavity within it. When a point charge q = +6.3 nC is placed into this cavity

How much charge will be found on each surface of the conductor?

inner: -6.3 nC (negative charge being attracted by the positive charge that being put in the cavity)
outer: 6.3 nC ( positive charge being pused to the outer radius)

if the conductor is grounded.

Charge on conductor surfaces:
inner: -6.3nC (negative charge being attracted by the positive charge that being put in the cavity)
outer: 0 nC ( because its being grounded, so positive charge travel to lower potential energy)

If the conductor was initially not neutral but has its own net charge of q2 = +4·q

Charge on conductor surfaces:
inner: . nC
outer: . nC




Homework Equations



no equation, its aconceptual questions

The Attempt at a Solution



i thought since the conductor is has more charge +4*q than the point charge , that means it will have -4*q as well. that means the point charge will not be able to pull electron near it. so inside charge will be -0 charge and outside will be +6.3
but I am wrong

then i think, well, maybe the point charge will be able to pull a fraction of - charge towards the cavity, so the charge inside will be -6.3 and outside will be 3*(6.3)=18.9

its wrong too

can someone kindly explain it to me? thank you for your time and reply
 
Physics news on Phys.org
TwinCamGTS said:

Homework Statement



a neutral conductor has a hollow cavity within it. When a point charge q = +6.3 nC is placed into this cavity

How much charge will be found on each surface of the conductor?

inner: -6.3 nC (negative charge being attracted by the positive charge that being put in the cavity)
outer: 6.3 nC ( positive charge being pused to the outer radius)

if the conductor is grounded.

Charge on conductor surfaces:
inner: -6.3nC (negative charge being attracted by the positive charge that being put in the cavity)
outer: 0 nC ( because its being grounded, so positive charge travel to lower potential energy)

If the conductor was initially not neutral but has its own net charge of q2 = +4·q

Charge on conductor surfaces:
inner: . nC
outer: . nC




Homework Equations



no equation, its aconceptual questions

The Attempt at a Solution



i thought since the conductor is has more charge +4*q than the point charge , that means it will have -4*q as well. that means the point charge will not be able to pull electron near it. so inside charge will be -0 charge and outside will be +6.3
but I am wrong

then i think, well, maybe the point charge will be able to pull a fraction of - charge towards the cavity, so the charge inside will be -6.3 and outside will be 3*(6.3)=18.9

its wrong too

can someone kindly explain it to me? thank you for your time and reply

You can think about this a little more accurately if you use use the Gauss theorem. What does that say? Add to that there is no electric field inside of a conductor.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top