Neutrino as alternative to Higgs boson

Jack Bauer
Messages
11
Reaction score
0
The Higgs boson was proposed to provide a mechanism for mass and is posited, as a field, to extend throughout the Universe. But this was before we started thinking the neutrino, which is also (almost) omnipresent, must have a mass. Could the neutrino substitute for the Higgs in this role?
 
Physics news on Phys.org
In the current Standard Model, neutrinos get their mass from the Higgs, just like all the other fundamental particles do. The coupling constant has to be different for each particle in order to get different masses. So far, those coupling constants have no well-accepted "explanation." We simply choose their values to give us the observed masses.

Before we inferred non-zero neutrino mass from the discovery of neutrino oscillations, we set the neutrino-Higgs coupling constants to zero, to agree with experiment up to that point. Now we set them to non-zero values. There's no fundamental difference in the theory.
 
Besides, the Higgs, as you can gather from its name, is a BOSON. A neutrino, it a FERMION. There's already a tremendous difference in physics between the two already. A simple substitution of each other's role is simply out of the question.

Zz.
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top