kky
- 7
- 0
just joined the forum
n(1/n) > (n+1)1/(n+1) for all n>=3.
k1/k > (k+1)1/(k+1)
=> k > (k+1)k/(k+1)
=> k+1 > (k+1)k/(k+1) + 1
=> (k+1)1/(k+1) > [(k+1)k/(k+1) + 1]1/(k+1)
I then tried binomial expansion of the term on the right.
leads to
(k+1)1/(k+1) > (k+1)k/(k+1)2 + 1/(k+1)*(k+1)[k/(k+1)][1/(k+1) -1] + (-k)/(2(k+1)2)*(k+1)[k/(k+1)][1/(k+1) - 2]...
But seem to be getting nowhere because of the negative term that appears and will continue to appear in every other term...
Am i on the right path?
apologies if it is too easy.
Homework Statement
n(1/n) > (n+1)1/(n+1) for all n>=3.
Homework Equations
The Attempt at a Solution
k1/k > (k+1)1/(k+1)
=> k > (k+1)k/(k+1)
=> k+1 > (k+1)k/(k+1) + 1
=> (k+1)1/(k+1) > [(k+1)k/(k+1) + 1]1/(k+1)
I then tried binomial expansion of the term on the right.
leads to
(k+1)1/(k+1) > (k+1)k/(k+1)2 + 1/(k+1)*(k+1)[k/(k+1)][1/(k+1) -1] + (-k)/(2(k+1)2)*(k+1)[k/(k+1)][1/(k+1) - 2]...
But seem to be getting nowhere because of the negative term that appears and will continue to appear in every other term...
Am i on the right path?
apologies if it is too easy.