New to the board. Can I get some guidance on a couple of questions?

AI Thread Summary
The discussion revolves around two physics problems involving angles of elevation and distances. The first problem requires calculating the height of an antenna based on the angles of elevation from a person's viewpoint, while the second problem involves determining the horizontal distance between two hot air balloons using trigonometric functions. The initial attempts at solutions yielded incorrect results, prompting the user to clarify their approach by defining variables for the heights involved. The user is encouraged to solve for the heights using tangent functions and then find the difference to determine the antenna's height. The focus remains on applying trigonometric principles correctly to arrive at the right answers.
lsumatt
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Homework Statement


1) The drawing shows a person looking at a building on top of which an antenna is mounted. The horizontal distance between the person's eyes and the building is d = 68.0 m. In part a the person is looking at the base of the antenna, and his line of sight makes an angle of θ1 = 35.0° with the horizontal. In part b the person is looking at the top of the antenna, and his line of sight makes an angle of θ2 = 40.0° with the horizontal. How tall is the antenna?

2) The two hot air balloons in the drawing are 48.2 and h = 56.0 m above the ground. A person in the left balloon observes that the right balloon is θ = 13.4° above the horizontal. What is the horizontal distance x between the two balloons?


Homework Equations


for the first i used cos and the second problem i used tan



The Attempt at a Solution


i got 57.1 km for the fist and 235 m for the second. but it says both are wrong
 
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ok i got #2 but still stuck on 1
 
Let a be the height of the base of the antenna off the ground

Let b be the height of the top of the antenna off the ground

\tan35^{\circ} = \frac{a}{68.0}

\tan40^{\circ} = \frac{b}{68.0}

Now you have to solve for a and b and find b-a
 
thanks!
 
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