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Newtonian Mechanics - single particle

  1. Feb 5, 2008 #1
    1. The problem statement, all variables and given/known data
    The speed of a particle of mass [m] varies with the distance[x] as v(x)=ax^(-n). Assume v(x=0)=0 at t=0.
    a)Find the force F(x) responsible
    b)Determine x(t)
    c)Determine F(t)

    2. Relevant equations



    3. The attempt at a solution
    My solution to part a is F(x)=-ma^2nx^(-2n-1).

    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
    Last edited: Feb 5, 2008
  2. jcsd
  3. Feb 5, 2008 #2

    pam

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    F=m(dv/dt), not what you did.
     
  4. Feb 5, 2008 #3
    Thats how i got to my answer for part a. I started with that and solved it to get F(x)=-ma^2nx^(-2n-1). This answer was also in the back of my book. Im stuck on part b and c.
     
  5. Feb 6, 2008 #4

    clem

    User Avatar
    Science Advisor

    The a in your first formula is not the acceleration.
    It is just an arbitrary constant.
     
  6. Feb 6, 2008 #5
    I know this already too. I put in "a" because I dont have a way to put in alpha.
     
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