Main Question or Discussion Point
Newton's THIRD law: implications on kinetic energy
edit: after thinking about it a little more, I realized something. After having landed, my kinetic energy becomes what it began as (practically zero). nvm then.kmarinas86 said:For every force, F, there is an equal and opposite force, -F. If the inertia of one object is greater than that of another object, the inertia of the greater object will do work on the smaller object, pushing it a distance, d.
If I jump forwards (due to the electromagnetic structure of the molecules of my body), the binding energy of my constituent molecules is increased, while I produce radiation as well as kinetic energy directed at the floor. Therefore, all other things equal, I add an impluse to the earth equal to the integral of (Force * time). Some of the kinetic energy impacts onto the earth becomes radiation. But the radiation has a (momentum*speed of light) which we can interpret as a radiative energy, as an analog to kinetic energy (since they are transformable to each other). The change in pressure*volume would therefore correspond to my change in kinetic energy+the change in my radiation + the change in the earth's kinetic energy + the change in earth's radiation... Would it not?
Would then change in pressure*volume correspond to 2*Fd, or while disregarding radiative loss, twice of the change in my kinetic energy, thus, mv^2?