A block A (mass 2.25k) rests on a tabletop. It is connected by a horizontal cord passomg over a light, frictionless pulley to a hanging block B (mass 1.3kg). The coeffisient of kinetic friction between block A and the tabletop is 0.45. After the block is released from the rest,
fint the speed of each block after moving 3cm.
The Attempt at a Solution
I found the frictionforce by:
Frictionforce = coeffisient * N (where N = G of block A).
Frictionforce = 9,93 N.
The force on the rope will be = the G (gravityforce) on block B.
ForceOnRope = 12,75N
Then I tried to use Newtons second law to find the acceleration, but this attempt failed when I tried to find the velocity of the boxes, which will be the same?