Newton's Method & Error Analysis

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SUMMARY

This discussion focuses on applying Newton's Method to solve the equation x ln(x) = 5, starting with an initial guess of x0 = 2. The results obtained were 3.77 and 3.769, accurate to 3 and 4 significant figures, respectively. Participants clarified the definitions of f(x) and f(~x), where f(x) represents the function evaluated at the approximate solution and f(~x) represents the function evaluated at the true value. The discussion emphasizes using the difference between the two results to estimate the absolute error, confirming that they approximate each other effectively.

PREREQUISITES
  • Understanding of Newton's Method for root-finding
  • Familiarity with logarithmic functions and their properties
  • Knowledge of error analysis and absolute error calculation
  • Basic calculus, specifically derivatives and their applications
NEXT STEPS
  • Study the derivation and application of Newton's Method in various contexts
  • Learn about error analysis techniques in numerical methods
  • Explore logarithmic functions and their behavior in equations
  • Investigate the concept of convergence in iterative methods
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Students and professionals in mathematics, engineering, and computer science who are interested in numerical methods, particularly those looking to enhance their understanding of root-finding algorithms and error analysis techniques.

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Homework Statement



(i) Use Newton’s Method and apparent convergence
to solve x ln(x) = 5 accurate to 3 and 4 significant figures. Start out with x0 = 2. (ii) Directly
approximate the absolute error on f, i.e. _f = f(x) − f(˜x). (iii) Use the difference between
the 4 significant figures and 3 significant figures results for x and the error formula to estimate
_f. You should find that they approximate each other.

Homework Equations



_f = ef'(x)

The Attempt at a Solution



I understand (i), I got 3.77 & 3.769.

For (ii), I don't understand what f(x) and f(~x) are. I know x is the measured value and ~x is the true value, but what are they in this case?

For (iii) do we take the difference to be the absolute error and the multiple it by the derivative at the true value?
 
Physics news on Phys.org
x is the solution you get using Newton's method and ~x is the "true" value. You can't know ~x, that's why they say "approximate".
 

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