Trouble Determining Moment Arm (aka Lever Arm)

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Homework Help Overview

The discussion revolves around determining the moment arm in a torque problem involving forces acting at angles. The original poster expresses difficulty in identifying the correct lengths of moment arms in a complex diagram, despite having successfully solved simpler problems previously.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants suggest breaking down the forces into their x and y components to aid in understanding the moment arms. There are inquiries about the relationships between angles in the diagram and the implications of right triangle properties.

Discussion Status

Participants are actively engaging with the original poster's confusion, offering hints and guidance on how to approach the problem. There is a recognition of the need to clarify angles and lengths in the diagram, with some participants reiterating the importance of labeling points for clarity. The discussion reflects a collaborative effort to explore the problem without reaching a definitive solution.

Contextual Notes

The original poster has expressed frustration with the complexity of the diagram and the challenge of applying previous knowledge to this specific case. There is an acknowledgment of the need for precise dimensions and angles to facilitate understanding.

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Homework Statement


1.png


Homework Equations


ΣM=Στ

The Attempt at a Solution


I know how to get the net torque about point P, but I am having difficulty determining where the moment arms for each force should be. I did 9 simpler questions before this no problem, but this diagram is a bit more complicated and I'm having trouble with it. The last three questions I have to do are all exactly the same (this one) with different numbers, so some help would be greatly appreciated!

I know the moment arm is the perpendicular distance from the line of action of the force to the point of rotation.

I am confused as how to find the length of the moment arms in this particular diagram. I think they should look like this (orange and blue lines)
1.png


But I am lost as to how to get their lengths (if where I have them is even correct).
 
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Hi,

Perhaps you could try to divide the forces F2 and F1 in the x and y directions.

Such that F2x = F2cos(A2), F2y = F2sin(A2), F1x = F1cos(A1), and F1y = F1sin(A1).

Hence, Your free body diagram would look a little like the attached picture.

Hope this answers your question!
 

Attachments

  • P_20160304_123415.jpg
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Look at the point where your blue line crosses the horizontal line at the bottom of the rectangle .

What do you know about the two acute angles there ?

What do you know about the sum of the angles in right angle triangles ?.
 
Last edited:
ShraZam said:
Hi,

Perhaps you could try to divide the forces F2 and F1 in the x and y directions.

Such that F2x = F2cos(A2), F2y = F2sin(A2), F1x = F1cos(A1), and F1y = F1sin(A1).

Hence, Your free body diagram would look a little like the attached picture.

Hope this answers your question!
I've tried this a few time and I haven't been able to get the correct answer :(
Do you spot a mistake I could have made?
If you can't read my writing I can type it out!
IMG_0270.jpg
 
Nidum said:
Look at the point where your blue line crosses the horizontal line at the bottom of the rectangle .

What do you know about the two acute angles there ?
I'm not sure, are they supposed to be the same?

Nidum said:
What do you know about the sum of the angles in right angle triangles ?.
They add up to 180 degrees.
 
This is messy, sorry, but I'm at this point in trying to figure the question out!
IMG_0271.jpg
 
Last edited:
Yes - they are the same . So what is the angle between your blue line and the left vertical line of the rectangle at point P ?
 
Nidum said:
Yes - they are the same . So what is the angle between your blue line and the left vertical line of the rectangle at point P ?
38.3 degrees
 
Yes - that angle and angle A1 are the same . Quick bit of trig now will give you length of blue line ?
 
  • #10
Hint : Work out the base length of the triangle below point P .
 
  • #11
Nidum said:
Hint : Work out the base length of the triangle below point P .
Tried it this way, still not getting correct answer
IMG_0272.jpg
 
  • #12
1-png.96777.png


This was your best diagram . Put in the actual dimensions and angles as given and add those that you have worked out so far .

Label all points where lines meet or cross . Simple a , b , c --- will suffice .
 
Last edited:
  • #13
ShraZam said:
Hi,

Perhaps you could try to divide the forces F2 and F1 in the x and y directions.

Such that F2x = F2cos(A2), F2y = F2sin(A2), F1x = F1cos(A1), and F1y = F1sin(A1).

Hence, Your free body diagram would look a little like the attached picture.

Hope this answers your question!

Nidum said:
This was your best diagram . Put in the actual dimensions and angles as given and add those that you have worked out so far .

Label all points where lines meet or cross . Simple a , b , c --- will suffice .

I eventually solved it using the first method I tried (breaking into x and y components.
Thanks for your help.
IMG_0275.jpg
 

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