- #1

jackxx

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[tex]\nabla \cdot B=0,[/tex]

so [tex]\int\nabla \cdot B dv=0,[/tex]

then [tex]\int B \cdot \widehat{n}da=0,[/tex]

let [tex]B=\nabla \times A,[/tex]

then [tex]\int\nabla \times A \cdot \widehat{n}da=0,[/tex]

thus [tex]A=\nabla\varphi[/itex], thus [tex]B=\nabla \times A=\nabla \times\nabla\varphi=0[/tex]

I know something is wrong with that but I am not sure what it is any ideas?

so [tex]\int\nabla \cdot B dv=0,[/tex]

then [tex]\int B \cdot \widehat{n}da=0,[/tex]

let [tex]B=\nabla \times A,[/tex]

then [tex]\int\nabla \times A \cdot \widehat{n}da=0,[/tex]

thus [tex]A=\nabla\varphi[/itex], thus [tex]B=\nabla \times A=\nabla \times\nabla\varphi=0[/tex]

I know something is wrong with that but I am not sure what it is any ideas?

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