Nodal Analysis Problem (Basic Circuit Analysis)

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SUMMARY

The discussion centers on solving a nodal analysis problem in basic circuit analysis, specifically finding voltages v1 and v2. The user applied Ohm's Law (V=IR) and current division to analyze a circuit with a 6A current source, resulting in a split of 2A through an 8-ohm resistor and 4A through a 4-ohm resistor. The user derived the equation (V2-V1) = 16 but struggled to formulate a second equation, suggesting the use of Kirchhoff's circuit laws. The final calculated values were v1 = 4.2V and v2 = 16.8V, with a total voltage of 33.6V.

PREREQUISITES
  • Understanding of Ohm's Law (V=IR)
  • Familiarity with current division principles
  • Knowledge of Kirchhoff's circuit laws
  • Basic skills in nodal analysis
NEXT STEPS
  • Study Kirchhoff's Voltage Law (KVL) for loop analysis
  • Learn advanced current division techniques in complex circuits
  • Explore nodal analysis with dependent sources
  • Practice solving circuit problems using simulation tools like LTspice
USEFUL FOR

Students and professionals in electrical engineering, particularly those focusing on circuit analysis and design, will benefit from this discussion.

Ginko
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Homework Statement


Find v1 and v2 from the given picture.


Homework Equations



Ohm's law, V=IR
Current Division

The Attempt at a Solution



I tried to use current division. The 6A source split into 2, giving 2A down the 8 ohm resistor and 4 amperes down the 4 ohm resistor. Since 10A goes out of the second node, 6A must come up from the ground.

I know one equation would be (V2-V1) = 16. I just can't seem to find the other equation. =/
 

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Physics news on Phys.org
Try Kirchhoff's circuit laws

You have three loop.

Besides, 8 Ohm:(4+2) Ohm
 
do you have the answers
I got v1 = 4.2 A & v2 = 16.8
and voltage = 33.6
I want to know if I did it right or not
 

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