Node-voltage Method, some misconception?

  • Thread starter Thread starter M. next
  • Start date Start date
  • Tags Tags
    Method
Click For Summary

Discussion Overview

The discussion revolves around the node-voltage method and its potential misconceptions, particularly in relation to the concept of essential nodes and nodal analysis. Participants explore the definitions and applications of these methods in circuit analysis.

Discussion Character

  • Debate/contested
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • Some participants assert that any node can be chosen as a reference point (GND) in the node-voltage method.
  • Others argue that an essential node must connect at least three components, raising questions about the validity of using nodes that connect only two components.
  • A participant questions the necessity of essential nodes in solving circuits using nodal analysis.
  • There is a request for clarification on the difference between nodal analysis and the node-voltage method, with a participant expressing familiarity only with the latter.
  • One participant claims that nodal analysis and the node-voltage method are essentially the same, providing an example to illustrate their point.
  • Another participant emphasizes that all voltages are measured with respect to the reference point, which is assumed to have zero voltage.

Areas of Agreement / Disagreement

Participants express differing views on the concept of essential nodes and their role in circuit analysis. While some agree on the flexibility of choosing reference points, others contest the implications of using nodes that do not meet the criteria of essential nodes. The discussion remains unresolved regarding the necessity and definition of essential nodes.

Contextual Notes

There are unresolved assumptions regarding the definitions of essential nodes and the conditions under which the node-voltage method can be applied. The discussion also highlights a lack of consensus on the relationship between nodal analysis and the node-voltage method.

M. next
Messages
380
Reaction score
0
Node-voltage Method, some misconception??

Please check the attachment:
The question is written upon it

Sorry bad drawing, the circuit is closed from the left hand side but not from the right hand side.
 

Attachments

  • Physics.png
    Physics.png
    6.1 KB · Views: 534
Last edited:
Engineering news on Phys.org


But I don't see any problem. We can choose any node we want as a reference point (GND).
 


But the essential node must connect at least 3 appliances! Here we have only two :/
 


But you can solve the circuit using nodal analysis without any "essential node".
And I still don't understand why you need "essential nodes"?
 


What's nodal analysis? How does it differ from node-voltage method. Elaborate please.
[I only learned node-voltage method :p]
If we are talking only node-voltage method, how in the world did the Doctor consider the node below a reference when it only connects two appliances[see figure].
That's my question.
 
Last edited:


I just checked, and they mean the same. Yet again, this is against the rule.
 
Last edited:


Nodal analysis is exactly the same think as node-voltage method.
And we can choose any node we want as a reference point (GND).

See the example

attachment.php?attachmentid=47008&stc=1&d=1336291275.png


We have a four nodes in our circuit. I pick as a reference point (GND) node 4.
So node 4 by de definition has a potential of 0 V.
So we left with three nodes. but we know that voltage at node 1 is equal 9V.
So we only has two unknown nodal voltages 2 and 3.
Now we apply KCL to the nodes where the unknown voltages appears.

For node 2 (I assume that all current flow out from the node)

[tex]\frac{V2}{R2} + \frac{V2 - V1}{R1} + \frac{V2 - V3}{R3} = 0[/tex]

And we notice that V1 = E1 = 10V

Now we write KCL for node 3.

[tex]\frac{V3 - V2}{R3} + \frac{V3 - V1}{R4} = 0[/tex]

And now all we have to do is to solve for V2 and V3

http://www.wolframalpha.com/input/?i=A/3+++(A+-+9)/9+++(A+-+B)/9+=0,+(B-A)/9+++(B+-+9)/9=0

V2 = 3V and V3 = Vth = 6V
 

Attachments

  • bez tytułu.PNG
    bez tytułu.PNG
    1.6 KB · Views: 657


Lots of thanks Jhony, now I get it..
 


We always measure all the voltage respect to this common point (reference point), also known as a "ground" (GND). And we assume that GND have zero voltage.
Look ta this examples

attachment.php?attachmentid=47009&stc=1&d=1336293980.png


attachment.php?attachmentid=42873&d=1327068105.jpg
 

Attachments

  • 0.1.PNG
    0.1.PNG
    6.9 KB · Views: 982
  • #10


Thanks, that's very kind of you.
You really were helpful
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 19 ·
Replies
19
Views
4K
Replies
12
Views
3K
  • · Replies 3 ·
Replies
3
Views
5K
Replies
20
Views
4K
Replies
15
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K