Non exact differential equation, initial value problem

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The discussion focuses on solving the non-exact differential equation y''' - 9y' = 54x - 9 - 20e^(2x) with initial conditions y(0) = 8, y'(0) = 5, and y''(0) = 38. The correct solution is identified as y = 2 + 2e^(3x) + 2e^(-3x) - 3x^2 + x + 2e^(2x). The main issue highlighted is an error in calculating the derivative y', specifically missing the constant term from the derivative of x. This oversight affected the coefficients C2 and C3 in the solution. The discussion emphasizes the importance of careful differentiation in solving initial value problems.
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Homework Statement


I am trying to solve the following:
y'''-9y'=54x-9-20e^2x with y(0)=8, y'(0)=5, y''(0)=38

Homework Equations

The Attempt at a Solution


upload_2016-12-8_9-34-25.png

upload_2016-12-8_9-34-52.png


The right answer is:
y= 2+2e^3x+2e^(-3x)-3x^2+x+2e^2x

I am only wrong on the coefficients C2 and C3. Where did I mess up in my solution?
 
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When computing ##y'## at the top of the second you are missing the constant ##1## coming from ##(x)'##=1.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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