Non-uniform circular motion, [stunt Car inside a ring]

AI Thread Summary
The discussion revolves around the forces acting on a stunt car executing non-uniform circular motion inside a ring. Participants clarify that at the bottom of the loop, the normal force (N) and weight (W) must balance to provide the necessary centripetal force for circular motion. It is emphasized that even though the speed is constant, the forces change, particularly N, which increases at the bottom compared to the top of the loop. The reasoning is compared to planes flying in circular loops, noting that similar principles apply, although the speed of a plane may vary. Understanding these dynamics is crucial for solving problems related to circular motion.
Krishan93
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Homework Statement


[PLAIN]http://img695.imageshack.us/img695/3864/unled1dxu.jpg

Homework Equations



F=(mv^2)/r

The Attempt at a Solution


NetForce=0
N-W=0

===
A free body diagram of the car at the bottom would just incorporate a downwards W force and an upwards N force together equalling 0, wouldn't it?
 
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Krishan93 said:
A free body diagram of the car at the bottom would just incorporate a downwards W force and an upwards N force together equalling 0, wouldn't it?
Those are the correct forces, but why would they add to 0? The car is accelerating!
 
Doc Al said:
Those are the correct forces, but why would they add to 0? The car is accelerating!

Accelerating as in change of direction?
I would think that the bottom of the loop is the maximum speed of the car, past that half the car begins to decelerate, no?
 
Krishan93 said:
Accelerating as in change of direction?
Yes. It's executing circular motion, so what kind of acceleration must exist?
I would think that the bottom of the loop is the maximum speed of the car, past that half the car begins to decelerate, no?
You are told that the speed is constant.
 
Doc Al said:
Yes. It's executing circular motion, so what kind of acceleration must exist?

You are told that the speed is constant.

I think I got it. Knowing constant velocity did help.
Given the top of the loop circumstances, the only forces acting upon the car are N and W, together they equal the centripetal force.
Keeping the same velocity at the bottom, the N and W act against each other, but the centripetal force still has to equal that of when it was at the top in order to maintain circular motion.
Apparently N takes on a greater value to compensate I guess and I get an answer of 20.1

How's my reasoning? Is this the same reasoning with planes flying in a circular loop as well?
 
Krishan93 said:
I think I got it. Knowing constant velocity did help.
Given the top of the loop circumstances, the only forces acting upon the car are N and W, together they equal the centripetal force.
Keeping the same velocity at the bottom, the N and W act against each other, but the centripetal force still has to equal that of when it was at the top in order to maintain circular motion.
Apparently N takes on a greater value to compensate I guess and I get an answer of 20.1
Good!
How's my reasoning? Is this the same reasoning with planes flying in a circular loop as well?
Similar considerations apply to anything moving in a vertical circle. (Of course, the speed of the plane will not necessarily be constant.)
 
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