- #1

Panphobia

- 435

- 13

## Homework Statement

## The Attempt at a Solution

So I just want to ask any of you who know physics pretty well if I am on the right track on this question, so it is asking for the magnitude of the acceleration of the car, and the direction. The magnitude of acceleration is (v^2/R) v = velocity and R = radius, so it is actually (at)^2/R where a = tangential acceleration, then plug in the numbers (0.75*20)^2/60 = 3.75 that is the centripetal acceleration. Now the magnitude of the acceleration of the car is just adding the radial acceleration and the tangential so sqrt(3.75^2 + 0.75^2) = 3.82 m/s^2. Now to get the direction, would I just use trigonometry for this?

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