Nonconservative gradients (not an oxymoron)

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In summary, the conversation discusses the relationship between a vector field and its curl, specifically in regards to the example of a vector field with the components (-y, x, 0). The conclusion is that this vector field is not a gradient of any surface, but it does have surfaces that are orthogonal to it at every point.
  • #1
okkvlt
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fx,fy=-y,x
curl(fx,fy)=2

its counterclockwise so the gradient is pointing ccw.
the gradient is the direction of max increase, so
then the surface z=f[x,y] whose gradient is -y,x is a spiral/screw whose z position goes up forever as x and y are traced out counterclockwise

so, a nonconservative field IS a gradient of a surface.
why was i lied to?
 
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  • #2
I think you're going to need to write this out clearer. How can the curl of a vector be a number? How can the gradient of a three variable equation be a two dimensional vector?
 
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  • #3
okkvlt said:
fx,fy=-y,x
curl(fx,fy)=2

its counterclockwise so the gradient is pointing ccw.
the gradient is the direction of max increase, so
then the surface z=f[x,y] whose gradient is -y,x is a spiral/screw whose z position goes up forever as x and y are traced out counterclockwise

so, a nonconservative field IS a gradient of a surface.
why was i lied to?

Hello there! Okay, let's take it step by step and yes, please do be a little clearer so we can understand exactly what you're saying. I think what you're saying is that you're trying to find the surface whose gradient at each point is (-y,x,0)? How did you make these out to be spirals?


So let's see, you've got the vector field:

[tex]\vec{V} = (-y, x, 0)[/tex]

Ye? And you've calculated its curl, which is:

[tex]Curl \vec{V} = (0,0,2)[/tex]

so the field is 'rotating' counterclockwise viewed from above (the positive z axis). The curl of your vector field is constant in all of space, and non-zero. Because it is non-zero means that your vector field [tex]\vec{V} = (-y, x, 0)[/tex] cannot be a gradient, in other words, there is no scalar field whose gradient is [tex]\vec{V}[/tex]. That is, there are no surfaces whose gradient at each point is (-y, x, 0). But! this does not mean that there are no surfaces which are orthogonal at each point to [tex]\vec{V}[/tex]. In fact, in your case, these surfaces DO exist, because the vector field [tex]\vec{V}[/tex] is normal to its curl.
 
  • #4
Just to help visualize, here is the curl of your vector field V, as viewed from above:

http://img31.imageshack.us/img31/4605/curl.gif
 
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FAQ: Nonconservative gradients (not an oxymoron)

What is a nonconservative gradient?

A nonconservative gradient is a type of gradient that does not conserve energy. In other words, it is a gradient that causes a change in energy, rather than maintaining a constant energy level.

How is a nonconservative gradient different from a conservative gradient?

A conservative gradient is a type of gradient that conserves energy, meaning that the total energy of a system remains constant as it moves through the gradient. In contrast, a nonconservative gradient causes a change in energy as a system moves through it.

What are some examples of nonconservative gradients?

Some examples of nonconservative gradients include friction, viscosity, and air resistance. These types of gradients cause a decrease in energy as a system moves through them.

How do nonconservative gradients affect the movement of objects?

Nonconservative gradients can slow down or hinder the movement of objects by causing a loss of energy. For example, friction can cause a ball to roll to a stop, as its energy is constantly being lost due to the nonconservative gradient of friction.

Are nonconservative gradients only present in physical systems?

No, nonconservative gradients can also be present in other systems, such as economic or social systems. In these cases, the nonconservative gradient may refer to a force or factor that causes a decrease in resources or stability, rather than a decrease in energy.

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