Nonlinear coordinate transformation

Click For Summary
SUMMARY

This discussion focuses on solving the 2-D diffusion equation within a bounded region defined by the lines y = mx + b and y = -mx - b. The user seeks to apply a nonlinear coordinate transformation to simplify the boundary conditions, mapping the curves to y = 1 and y = 0. The transformation T must satisfy T(x, mx) = (x, 1) and T(x, -mx) = (x, 0), indicating a need for a nonlinear mapping from (x, y) to (x', y'). The user is looking for assistance in deriving the relationships x = f(x', y') and y = g(x', y') to facilitate the transformation of derivatives in the PDE.

PREREQUISITES
  • Understanding of 2-D diffusion equations
  • Familiarity with coordinate transformations
  • Knowledge of linear algebra concepts, particularly basis and transformations
  • Experience with numerical methods for PDEs
NEXT STEPS
  • Research nonlinear coordinate transformations in PDEs
  • Study the method of characteristics for solving PDEs
  • Explore numerical techniques for boundary value problems
  • Learn about mapping techniques in computational fluid dynamics
USEFUL FOR

Mathematicians, physicists, and engineers working on partial differential equations, particularly those dealing with diffusion processes and numerical simulations.

shawnstrausser
Messages
4
Reaction score
0
Evening all,

I'm trying to solve the 2-D diffusion equation in a region bounded by y = m x + b, and y = -m x -b. The boundary condition makes it complicated to work with numerically, and I recall a trick that involves a coordinate transformation so that y = m x + b, and y = -m x -b are mapped to y = 1, and y = 0, which I already have a program to solve numerically. This will transform the PDE, but that is easier (I think) to work with..

My attempt:
I simplified the problem to first consider y = m x, and y = - m x.
The curve y = m x can be written as (x, m x), and y = - m x as (x, -m x).
The transformation, T, should satisfy T(x, m x) = (x, 1) and T(x, - m x) = (x,0). As far as I can tell, (x, m x), and (x, - m x) form a basis(?) and so this should completely determine the transformation, from what I recall in Linear Algebra (or maybe that only works for a linear transformation?). It looks like the transformation is non linear as well. I'm not quite sure where to go, I want to map from the coordinates (x,y) to (x',y') that transform the curves as described above. If I could find the relationships x = f(x',y') and y = g(x',y'), then I could transform the derivatives in the PDE. Any help would be appreciated! Thank you in advance..
 
Physics news on Phys.org
Just realized I posted in the wrong section...sorry
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 26 ·
Replies
26
Views
1K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 52 ·
2
Replies
52
Views
4K
  • · Replies 12 ·
Replies
12
Views
5K
  • · Replies 41 ·
2
Replies
41
Views
4K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 20 ·
Replies
20
Views
4K