- #1
SolCon
- 33
- 1
Hello to all.
Simple question but I'm getting the wrong answer here.
Question:
The random variable X is normally distributed with mean μ and variance 21.0. Given that
P(X > 10.0) = 0.7389, find the value of μ.
The equation we'll use is thus: z=(x-μ)/SD
So, what I did was:
0.64 ([tex]\phi[/tex]0.7389) = (10-μ)/under.root.21
(0.64)(under.root.21)-10=-μ
2.9-10=-μ
-7.1=-μ
μ=7.1
This answer is wrong for some reason and I have no idea why this is so. Any help here is appreciated.
Simple question but I'm getting the wrong answer here.
Question:
The random variable X is normally distributed with mean μ and variance 21.0. Given that
P(X > 10.0) = 0.7389, find the value of μ.
The equation we'll use is thus: z=(x-μ)/SD
So, what I did was:
0.64 ([tex]\phi[/tex]0.7389) = (10-μ)/under.root.21
(0.64)(under.root.21)-10=-μ
2.9-10=-μ
-7.1=-μ
μ=7.1
This answer is wrong for some reason and I have no idea why this is so. Any help here is appreciated.