Normal Distribution Homework: Expectation and Variance for Sample of 25 Students

AI Thread Summary
The discussion focuses on deriving the expectation and variance for the mean score of 25 students from a normally distributed SAT score population with an average of 600 and a standard deviation of 75. The expectation of the sample mean (Y) is equal to the population mean, while the variance is calculated as the population variance divided by the sample size (n), specifically 75^2/25. To determine the probability that Y exceeds 610, the z-score for 610 must be calculated, which involves using the formula for the standard deviation of the sample mean. The final step is to use the z-score to find the probability from standard normal distribution tables or a calculator. Understanding these concepts is crucial for solving the problem effectively.
Maybe_Memorie
Messages
346
Reaction score
0

Homework Statement



Students of a US university have an average SAT score of 600 and a standard deviation of 75. Assume the scores are distributed as a normal distribution.

If X is the score of a randomly selected student, derive the expectation and variance of the mean score, Y, of n randomly selected students.

If the sample is of n=25 students, what is the probability Y exceeds 610?

Homework Equations





The Attempt at a Solution



For a normal distribution, the expectation is the mean, and the variance is the standard deviation squared, so am I correct in saying for n students it would be n times this value?

As for the second part, I'm lost
 
Physics news on Phys.org
excuse lack of latex code here.

from my general statistics book:

1. Yes, the mean of x(bar) is the population mean.
2. The standard deviation of the sample is sigma/sqrt(n).

You need to calculate the z score of 610. Then use this with standard tables, or calculator to find P(.67<Z<Infinity).
 
Back
Top