Normal force in circular motion, is my work correct

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SUMMARY

The forum discussion centers on deriving the normal force in circular motion. The user correctly identifies the relationship between normal force (N), gravitational force, and centripetal acceleration. The final expression derived is N = m(v²/r) + mgcos(theta), which accurately represents the normal force acting on an object in circular motion at an angle theta. This formulation is essential for solving problems involving forces in circular dynamics.

PREREQUISITES
  • Understanding of Newton's second law (F = ma)
  • Knowledge of centripetal acceleration (a_c = v²/r)
  • Familiarity with trigonometric functions, specifically cosine
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the derivation of centripetal force in circular motion
  • Explore applications of normal force in inclined planes
  • Learn about the effects of varying speed on normal force
  • Investigate the role of friction in circular motion scenarios
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators looking for clear examples of force analysis in dynamic systems.

fishingspree2
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Homework Statement


If:
weight = m
speed = v
angle = theta
radius = r

Write an algebric expression that is equal to the Normal force


Homework Equations


F = ma
acentr. = v2/r

The Attempt at a Solution


N -mgcos(theta) = m v2/r
N = m v2/r +mgcos(theta)

correct?
 
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