Normal Subgroup of Prime Index: Properties

dori1123
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Show that if H is a normal subgroup of G of prime index p, then for all subgroups K of G, either
(i) K is a subgroup of H, or
(ii) G = HK and |K : K intersect H| = p.
 
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Well, what have you tried? And is G a finite group?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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