- #1
MarkoA
- 13
- 1
Hi,
I'm not sure about the the normal vector N on a complex function
[tex] z(x,t) = A e^{i(\omega t + \alpha x)} [/tex]
My approach is that ([itex]\overline{z}[/itex] beeing the conjugate of [itex]z[/itex]):
[tex]
\Re{(\mathbf{N})} = \frac{1}{\sqrt{\frac{1}{4}(\partial x + \overline{\partial x} )^2 + \frac{1}{4}(\partial z + \overline{\partial z} )^2 }} \begin{bmatrix}
-\frac{1}{2}(\partial z + \overline{\partial z}) \\
\frac{1}{2}(\partial x + \overline{\partial x})
\end{bmatrix}
[/tex]
and
[tex]
\Im{(\mathbf{N})} = \frac{1}{\sqrt{-\frac{1}{4}(\partial x - \overline{\partial x} )^2 -\frac{1}{4}(\partial z - \overline{\partial z} )^2 }} \begin{bmatrix}
-\frac{1}{2i}(\partial z - \overline{\partial z}) \\
\frac{1}{2i}(\partial x - \overline{\partial x})
\end{bmatrix}
[/tex]
So I have [itex] \frac{\partial z}{\partial x} = i\omega A e^{i(\omega t + \alpha x)} [/itex]. Do I now choose [itex]\partial x = 1 + i[/itex] for the complex x-component? Can I see the imaginary part of the normal vector as the normal vector on the imaginary part of z? Or is my approach wrong?
Thanks!
I'm not sure about the the normal vector N on a complex function
[tex] z(x,t) = A e^{i(\omega t + \alpha x)} [/tex]
My approach is that ([itex]\overline{z}[/itex] beeing the conjugate of [itex]z[/itex]):
[tex]
\Re{(\mathbf{N})} = \frac{1}{\sqrt{\frac{1}{4}(\partial x + \overline{\partial x} )^2 + \frac{1}{4}(\partial z + \overline{\partial z} )^2 }} \begin{bmatrix}
-\frac{1}{2}(\partial z + \overline{\partial z}) \\
\frac{1}{2}(\partial x + \overline{\partial x})
\end{bmatrix}
[/tex]
and
[tex]
\Im{(\mathbf{N})} = \frac{1}{\sqrt{-\frac{1}{4}(\partial x - \overline{\partial x} )^2 -\frac{1}{4}(\partial z - \overline{\partial z} )^2 }} \begin{bmatrix}
-\frac{1}{2i}(\partial z - \overline{\partial z}) \\
\frac{1}{2i}(\partial x - \overline{\partial x})
\end{bmatrix}
[/tex]
So I have [itex] \frac{\partial z}{\partial x} = i\omega A e^{i(\omega t + \alpha x)} [/itex]. Do I now choose [itex]\partial x = 1 + i[/itex] for the complex x-component? Can I see the imaginary part of the normal vector as the normal vector on the imaginary part of z? Or is my approach wrong?
Thanks!